What will be the volume of a 10 m high prism whose base is a regular p

1.	What will be the volume of a 10 m high prism whose base is a regular polygon with each side 2 m and internal angle of 120°? Given(√3 = 1.7)1. 102 cm32. 204 m33. 51 m34. 102 m3
Answer» Correct Answer - Option 4 : 102 m³ Given- Height of prism = 10 m Each Side of polygon = 2 m Each interior angle = 120° Concept Used- Volume of Prism = Area of Base × Height Area of Hexagon = 3√3/2 × Side² Each External Angle of a polygon = 360/n [where n = number of sides of the polygon] Calculation- Exterior Angle = 180° - 120° ⇒ 60° n = 360/60 ⇒ 6 Hence the polygon is a regular hexagon. Area of Hexagon = 3√3/2 × 2² ⇒ 6√3 m² ∴ Volume of Prism = 6√3 × 10 ∵ √3 = 1.7(given) ⇒ 102 m³

What will be the volume of a 10 m high prism whose base is a regular polygon with each side 2 m and internal angle of 120°? Given(√3 = 1.7)1. 102 cm32. 204 m33. 51 m34. 102 m3

Answer» Correct Answer - Option 4 : 102 m³

Given-

Height of prism = 10 m

Each Side of polygon = 2 m

Each interior angle = 120°

Concept Used-

Volume of Prism = Area of Base × Height

Area of Hexagon = 3√3/2 × Side²

Each External Angle of a polygon = 360/n [where n = number of sides of the polygon]

Calculation-

Exterior Angle = 180° - 120°

⇒ 60°

n = 360/60

⇒ 6

Hence the polygon is a regular hexagon.

Area of Hexagon = 3√3/2 × 2²

⇒ 6√3 m²

∴ Volume of Prism = 6√3 × 10 ∵ √3 = 1.7(given)

⇒ 102 m³

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What will be the volume of a 10 m high prism whose base is a regular polygon with each side 2 m and internal angle of 120°? Given(√3 = 1.7)1. 102 cm32. 204 m33. 51 m34. 102 m3

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