1.

What will be the volume of CO_(2) at S.T.P., obtained by heating 9.85g of BaCO_(3) (atomic number of Ba=137)

Answer»

1.12 LITRE
0.84 litre
2.24 litre
4.06 litre

Solution :`BaCO_(3) to BaO+CO_(2) UARR`
`therefore197g" "BaCO_(3)` on DECOMPOSE gives=22.4litre `CO_(2)`
`therefore1g" "BaCO_(3)` will give`=(22.4)/(197)="litre "CO_(2)`
`=(22.4xx9.85)/(197)=1.12"litre "CO_(2)`


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