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What will be the volume of `pH` of `0.01` mold`m^(-3)` `CH_(3)COOH(K_(a) = 1.74 xx 10^(-5))`A. `3.4`B. `3.6`C. `3.9`D. `3.0` |
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Answer» Correct Answer - A `H^(+)= sqrt(K_(a)xxC)` `=sqrt(174xx10^(-7))=sqrt(174.4xx10^(-8))` `=4.2xx10^(-4)` `ph=-log[4.2xx10^(-4)]` `=(4-log4.2)` `=4-0.6232=3.3768` `approx 3.4` |
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