1.

What will be the volume of `pH` of `0.01` mold`m^(-3)` `CH_(3)COOH(K_(a) = 1.74 xx 10^(-5))`A. `3.4`B. `3.6`C. `3.9`D. `3.0`

Answer» Correct Answer - A
`H^(+)= sqrt(K_(a)xxC)`
`=sqrt(174xx10^(-7))=sqrt(174.4xx10^(-8))`
`=4.2xx10^(-4)`
`ph=-log[4.2xx10^(-4)]`
`=(4-log4.2)`
`=4-0.6232=3.3768`
`approx 3.4`


Discussion

No Comment Found

Related InterviewSolutions