1.

What will be the volume of the mixture after the reaction :NH_3 (g) (1L) + HCl (g) (1.5L) toNH_4Cl (s)

Answer»

1.5 L
0.5 L
1L
0L

Solution :1L of `NH_3` (G) reacts with 1L HCL (g) to form `NH_4Cl (s)` which has NEGLIGIBLE volume . HENCE FINAL mixture will contain only 0.5 L of HCl


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