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What will be the volume strength of 100 ml of `H_(2)O_(2)` required to react completely with 61 ml of `KMnO_(4)` in acidic medium ? ( Given that `61 l` of `KMnO_(4)` reacts completely with 5 ml of 1M of `K_(4)[Fe(CN)_(6)]` where it converts into `K^(+),Fe^(3+),CO_(3)^(2-)` and `NO_(3)^(-)` )A. `17.08`B. `34.2`C. `18.8`D. `19.8` |
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Answer» Correct Answer - 1 Valency factor of `K_(4)[(Fe(CN)_(6)]=61` so of molarity of `H_(2)O_(2)=x M` than `implies2x xx100=5xx61xx1` `[` for `KMnO_(4). 61xxyxx5=5xx61xx1impliesy=1M]` So, `x=(305)/(200)=1.525.` So , volume strength `=17.08` |
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