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What will be the wavelength of the emitted radiations when an electron jumps from a third orbit to a first orbit in a hydrogen atom? Rydberg constant, R= 109737 cm^(-1) |
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Answer» Solution :We have for hydrogen (Z=1) `(1)/(lamda)= R ((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))` Here `n_(1)=1 and n_(2)=3` `THEREFORE (1)/(lamda)= 109737 ((1)/(1^(2)) - (1)/(3^(2)))` `lamda= 1.025 xx 10^(-5)` cm/wave |
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