What will happen during the electrolysis of aqueous solution of `CuSO_(4)` by using platinum electrodes ?A. Copper will deposit at cathodeB. Copper will deposit at anodeC. Oxygen will be released at anodeD. Copper will dissolve at anode.

What will happen during the electrolysis of aqueous solution of `CuSO_

1.	What will happen during the electrolysis of aqueous solution of `CuSO_(4)` by using platinum electrodes ?A. Copper will deposit at cathodeB. Copper will deposit at anodeC. Oxygen will be released at anodeD. Copper will dissolve at anode.
Answer» Correct Answer - A::C (a, c) are both correct options.

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Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

What will happen during the electrolysis of aqueous solution of `CuSO_(4)` by using platinum electrodes ?A. Copper will deposit at cathodeB. Copper will deposit at anodeC. Oxygen will be released at anodeD. Copper will dissolve at anode.

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