1.

What will happen to the volume of a bubble of air found under water in a lake, where the temperature is 15^(@)C and the pressure is 1.5 atm. If the bubble then rises to the surface where the temperature is 25^(@)C and the pressure is 1.0 atm ?

Answer»

Its volumewill become GREATER by a factor of 2.5
Its volumewill become greater by a factor of 1.6
Its volumewill become greater by a factor of 1.1
Its volumewill become greater by a factor of 0.70

Solution :`(p_(1)V_(1))/( T_(1)) = ( p _(2) V_(2))/( T_(2))`
`p_(1) = 1.5 atm, T_(1) = 273 + 15 = 288 K `
`p_(2) = 1.0 atm, T_(2) = 273 + 25 = 298 K`
`( 1.5 xx V_(1)) /( 288) = ( 1 xx V_(2))/( 298)`
`V_(2) = ( 1.5 xx V_(1) xx 298)/(288 xx 1 )`
`1.55 V_(1) = 1.6 V_(1)`


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