1.

What will the PH of a solution formed by mixing equal volumes of two solutions A and B having PH=6 and PH=4

Answer»

 PH=6 

[H+ ] = 10-6

PH=2 

[H+ ] = 10-2

Resultant [H+

M1xV1+M2xV2=M3 xV3 10-6 x1 +10-6 x1=M3x2 

M3=101x10-6 /2 = 50. 5 x 10-6 

PH=- log(50.5x10-7

 =4.296



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