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What will the PH of a solution formed by mixing equal volumes of two solutions A and B having PH=6 and PH=4 |
Answer» PH=6 [H+ ] = 10-6 M PH=2 [H+ ] = 10-2 M Resultant [H+ ] M1xV1+M2xV2=M3 xV3 10-6 x1 +10-6 x1=M3x2 M3=101x10-6 /2 = 50. 5 x 10-6 PH=- log(50.5x10-7 ) =4.296 |
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