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What work has to be done to make a hoop out of a copper band of length l=3m,width h=6 cm and thickness delta =1mm? (Y of copper =1.3xx10^(11) ""Nm^(-2) ) [Hint: Consider strain energy in a a thin layer and intergraate from r-delta//2 "to" r+delta//2]

Answer»


ANSWER :`(1)/(6)pi^(2)hdelta^(3)Y//=80J`


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