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What would be the pH of 0.1 molar sodium acetate solution, given that the dissociation constant of acetic acid is 1.8xx10^(-5). |
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Answer» `pH = 7 + (1)/(2) [ pK_(a)+log c] = 7 + (1)/(2) [- log (1.8xx10^(-5))+log 0.1] = 7 + (1)/(2) [ 4.76xx-1] = 8.88` |
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