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What would have been the shape of benzene molecule had there been no resonance ? |
Answer» SOLUTION :Due to resonance, delocalization of SIX `PI`-electrons takes place. As a result, all the carbon-carbon bonds in benzene are equal (139 pm) and the molecule is SYMMETRICAL. Had there been no resonance, benzene would be an unsymmetrical molecule consisting of three carbon-carbon single bonds (154 pm) and three carbon-carbon double bonds (134 pm) as SHOWN ?
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