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Whatare thefrequencyand wavelengthofaphoton emittedduringa transitionfromn=5stateto the n=2statein the hydrogenatom ? |
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Answer» Solution :Sinceinitialenergystate `n_(i)=5 ` calculateof `Delta E ` `Delta E = 2.18 xx 10^(18)((1)/(n_(1)^(2)) - (1)/( n_(f ) ^(2)))` =`2.18 xx 10^(18)((1)/(5^(2)) - (1)/(2^(2)))J` Calculationof FREQUENCYOF photon( v) : `v= (Delta E)/(h ) ` ` (4.578 xx 10^(18))/( 6.625 xx 10^(34) J s) ` Calculationof waveleng `(lambda)` `= (3.0 xx 10^(18) ms^(-1))/(6.9091 xx 10^(14) s^(1))` `lambda=434.21 NM` |
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