1.

Whatare thefrequencyand wavelengthofaphoton emittedduringa transitionfromn=5stateto the n=2statein the hydrogenatom ?

Answer»

Solution :Sinceinitialenergystate `n_(i)=5 `
calculateof `Delta E `
`Delta E = 2.18 xx 10^(18)((1)/(n_(1)^(2)) - (1)/( n_(f ) ^(2)))`
=`2.18 xx 10^(18)((1)/(5^(2)) - (1)/(2^(2)))J`
Calculationof FREQUENCYOF photon( v) :
`v= (Delta E)/(h ) `
` (4.578 xx 10^(18))/( 6.625 xx 10^(34) J s) `
Calculationof waveleng `(lambda)`
`= (3.0 xx 10^(18) ms^(-1))/(6.9091 xx 10^(14) s^(1))`
`lambda=434.21 NM`


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