1.

Whatis the molarconductivity of Aglat zeroconcentrationif the ^^_(0) valuesof NaI, AgNO_(3)and NaNO_(3) arerespectively126.9 Omega^(-1) cm^(2)mol^(-1),133.4 Omega^(-1) cm^(2) mol^(-1)and121.5 Omega^(-1) cm^(2)mol^(-1)?

Answer»


Solution :Given : `^^_(o_((NAI)))= 126. 9 OMEGA^(-1)cm^(2) MOL^(-1)`
` ^^_(o_((AgNO_(2)))) = 133.4 Omega^(-1)cm^(2)mol^(-1)`
`^^_(o_((NaNO_(3)))) = 121. 5 Omega^(-1)cm^(2)mol^(-1)`
ByKohlrausch'slaw
`^^_(o_((Agl))) = lambda_(Ag^(+))^(o) +lambda_(i^(-))^(0) ""......(I)`
`^^_(o_((NaI)))= lambda_(Ag^(+))^(0) +lambda_(I^(-))^(0) ""......(i)`
`^^_(o_((AgNO_(3))))= lambda_(Ag^(+))^(0) + lambda_(I^(-))^(0)""......(ii)`
`^^_(o_((NaNO_(3))))= lambda_(Na^(+))^(0) + lambda_(NO_(3))^(3)`
Addingequation(i) and(ii) andsobtractingequation (iii)we getequation I.
`^^_(0_((Agl)))= ^^_(0_((NaI))) + ^^_(0_((AgNO_(3)))).^^(0_((NaNO_(3)))`
`= 126.9 + 133.4 - 121 .5 `
`=138. 8 Omega^(-1)cm^(2) mol^(-1)`


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