1.

Whatis the number of moles of Fe (OH)_(3) (s) that can be producedby allowing 1 mole of Fe_(2)S_(3) , 2 moles of H_(2) Oand 3 molesof O_(2) to react?2 Fe_(2) S_(3) (s) + 6H_(2) O (1) + 3O_(2) (g) to 4Fe (OH)_(3) (s) + 65 (s)

Answer»

Solution :Fromthe givenmole ratio of `Fe_(2)S_(3) , H_(2) O and O_(2)` (i.e., 1 : 2 : 3) and moleratioin the reaction , (i.e.,e: 6 : 3) it is clearthat `H_(2) O`is the limitingreagent as `H_(2)O`SHALL befullyconsumed in the reaction. Thus,
MOLESOF `Fe(OH)_(3)` produced by2 molesof `H_(2) O = (4)/(6) XX 2 = 1. 34`


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