Whatweight of CO is required to form Re_(2) (CO)_(10) from 2 . 50 g of Re_(2) O_(7) accordingto theunbalanced reaction : Re_(2) O_(7) + CO to Re_(2) (CO)_(10) + (CO_(2)(Re = 186 . 2 , C = 1 and O = 16)

Whatweight of CO is required to form Re_(2) (CO)_(10) from 2 . 50 g of

1.	Whatweight of CO is required to form Re_(2) (CO)_(10) from 2 . 50 g of Re_(2) O_(7) accordingto theunbalanced reaction : Re_(2) O_(7) + CO to Re_(2) (CO)_(10) + (CO_(2)(Re = 186 . 2 , C = 1 and O = 16)
Answer» Solution :Suppose the RELATIVE moles of each reactantand product are as follows (just for convenience) `{:(Re_(2)O_(7)"" + CO "" to ""Re_(2) (CO)_(10)"+ "CO_(2)),(" a molesb molesc molesd moles "):}` Applying POAC for Re atoms, `{:(" moles of Re in " Re_(2) O_(7) =" moles of Re in " RE_(2) (CO)_(10)),(" "2 xx "moles of " Re_(2) O_(7) = 2 xx "moles of " Re_(2) (CO)_(10)),("Ra = 2c"),("ora = c" ):}`. . . (i) ApplyingPOAC for C atoms, moles of C atoms in CO = molesof C in `Re_(2) (CO)_(10) ` + moles of C in ` CO_(2)` `xx` molesof CO ` = 10 xx ` moles of `Re_(2) (CO)_(10) + 1 xx` moles of `CO_(2)` or b = 10 c + d. . . (II) moles of O in `Re_(2) O_(7) ` + molesof O in CO = molesof O in `Re_(2) (CO)_(10) + ` moles of O in `CO_(2)` `7 xx ` moles of `Re_(2)O_(7) + 1 xx `molesof CO `= 10 xx` molesof `Re_(2) (CO)_(10) + 2 xx ` moles of `CO_(2)` or `7a + b = 10 c + 2 d""` . . . (iii) Fromthe eqns . (i),(ii)and (iii) , we get17 a = b i.e., `17 xx ` moles of `Re_(2) O_(7)`= moles of CO `17 xx (2 . 50)/( 484,.4) = ("wt . of CO in G")/(28) [{:(mol. wt. of Re_(2) O_(7) = 484.4),("mol. wt. of CO = 28"):}] ` Wt . of CO = 2 . 46g