1.

When 0.01 mole of sugar is dissolved in 100g of a solvent, the glucose is dissolved in 50 g of the same solvent, the depression in freezing point will be

Answer»

`0.60^(@)`
`0.80^(@)`
`1.60^(@)`
`2.40^(@)`

Solution :`DELTA T_(F)=mk_(f)`
`0.40=(0.01xx1000)/(100)xx k_(f)rArr k_(f)=4`
again `Delta T_(f)=mk_(f)`
`=(0.03xx1000)/(50)xx4=2.4`


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