1.

When 0.1 mole of glucose is dissolved in 10 mole of water, the vapour pressure of water is

Answer»

Increased by 1%
Increased by 10%
Decreased by 1%
Decreased by 10%

SOLUTION :ACCORDING to Raoult.s law,
`(p_(A)^(@)-p_(A))/(p_(A)^(@))=x_(B)`
or `(DELTAP)/(p_(A)^(@))=(n_(B))/(n_(A)+n_(B))`
`(Delta p)/(p_(A))=(0.1)/(10+0.1)~~(0.1)/(10)=(1)/(100)=1%`


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