When 0.15 mol of Ammonia is dissolved in water to make 1 L of solut – InterviewSolution

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1.	When 0.15 mol of Ammonia is dissolved in water to make 1 L of solution, the [OH]− of solution is 1.34×10−3M. Calculate Kb for NH3.
Answer» When $0.15 m o l$ of Ammonia is dissolved in water to make $1 L$ of solution, the $[O H]^{-}$ of solution is $1.34 \times 10^{- 3} M$ . Calculate $K_{b}$ for $N H_{3}$ .

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