1.

When 0.2 mole of anhydrous CuSO_(4)is dissolved in water, the heat evolved is 1.451 kcal. If 0.2moleof CuSO_(4).5H_(2)Ois dissolved in water, the heat absorbed is 0.264 kcal. Calculate the molar heat of hydration of CuSO_(4)

Answer»

11.87 kcal
`-11.87` kcal
17.15 kcal
`-17.15` kcal

Solution :(i) `CuSO_(4)(s)+"aqua"toCuSO_(4)(AQ)`
`DELTA=(-1.451)/0.1=-14.51k "cal MOL"^(-1)`
(ii)`CuSO_(4).5H_(2)O(s)+"aqua"toCuSO_(4)(aq)`
`Deltah=0.264/0.1=2.64 K "cal mol"^(-1)`
From i-ii
`CuSo_(4)(s)+5H_(2)O(l)toCuSO_(4).5H_(2)O(s),`
`DeltaH=-17.15k "cal mol"^(-1)`


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