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When 0.6 g of urea is dissolved in 100 g of water, the water will boil at ( K_(b) for water = 0.52 Km^(-1) and normal boiling point of water = 100^(@)C ) : |
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Answer» 372.48 K `=(0.52xx0.6xx1000)/(100xx60)=0.052^(@)C` Boiling point of solution `=373+0.052` `=373.052` |
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