1.

When 1.0 g of a non-volatie solute was dissolved in 10 g benzene, elevation in boiling point temperature was found to be 1^(@)C. Calculate the molar mass of the dissoved substance. (K_(b) "for benzene = 2.53 K kg" mol^(-1)).

Answer»


Solution :`W_(B)=1.0g, W_(A)=10g=0.01 kg`
`DeltaT_(b)=1^(@)C or 1 K, K_(b)=2.53" K kg MOL"^(-1)`
`M_(B)=(K_(b)xxW_(B))/(DeltaT_(b)xxW_(A))=((2.53" K kg mol"^(-1))xx(1.0 G))/((1 K)xx(0.01" kg"))=253" g mol"^(-1)`


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