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When `1.0 xx 10^12`electrons are transferred from one conductor to another, a potential difference of `10 V` find the capacitance of the two -conductor system . |
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Answer» Here, charge transferred, Q =n e `Q = (1.0xx10^(12)) (1.6xx10^(-19)) C` `= 1.6xx10^(-7)C` , V = 10 Volt, C = ? As `C = (Q)/(V) = (1.6xx10^(-7))/(10) = 1.6xx10^(-8) F` |
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