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When `1.0xx10^(12)` electrons are transferred from one conductor to another, a potential difference of 10 V appears between the conductors. Find the capacitance of this two conductor system.A. `2.32xx10^(-4)F`B. `1.6xx10^(-8)F`C. `1.2xx10^(-6)F`D. None of these |
Answer» Correct Answer - B Number of electrons, `n=1.0xx10^(12)` `therefore" Charge transferred, Q "=n e =1.0xx10^(12)xx1.6xx10^(-19)` `=1.6xx10^(-7)C" "(because e=1.6xx10^(-19)C)` Capacitance between two conductors, `C=(Q)/(V)=(1.6xx10^(-7))/(10)=1.6xx10^(-8)F` |
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