1.

when 1.8 g of steam at the normal boiling point of water is converted inot water ,at the same temperature , enthalpy and entropy changes respectively will be[given , DeltaH_("vap")for water =40.8 KJ mol^(-1) ]

Answer»

`-8.12kJ,11 .89Jk^(-1)`
`10.25 kJ,12 .95 Jk ^(-1)`
`- 4.08 kJ,-10.93 JK^(-1)`
`10.93 KJ, -4.08 JK^(-1)`

Solution :` DeltaH("CONDENSATION") for 1.8 g of steam `
` = (-40.8)kJ XX (1.8/18) MOL =- 4.08 KJ`
` DeltaS= (DeltaH)/(T_(B))= (-4.08xx10^(3)J)/(373.15 K ) =- 10.93 JK^(-1)`


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