1.

When 1 mole of oxalic acid is treated with excess of NaOH in dilute aqueous solution 108kJ of heat is liberated ,then the enthalpy of ionization of the oxalic acid is(Given H^+(aq)+OH^-(aq)rarrH_2O(l)Delta_neulH=-57.3kJ)

Answer»

`4.6kJ MOL^(-1)`
`-4.6kJ mol^(-1)`
`-6.6kJ mol^(-1)`
`6.6kJ mol^(-1)`

ANSWER :D


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