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When 1 N forceis applied increase in length ofthe springis 1 cm . Find elastic potential energystoredduringthis in it . |
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Answer» `10 xx10^(-3)J ` (neglectingnegativesign ) ` U = 1/2 kx^(2) = 1/2 xx10^(2) XX (10^(-2))^(2)` ` = 5xx10^(-3) J ` . |
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