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When 10 gm of BaCl_(2)xxH_(2)O are heated, the residue of anhydrous BaCl_(2) weighs 8.53 gm. The value of x is

Answer»

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Solution :`(10)/((137.34+2xx35.5)+ 18 X)=(8.53)/(137.34+2xx35.5)`
`THEREFORE x=2`


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