1.

When 10 ml of 0.1 M acetic acid (pK_(a) = 5.0) in titrated against 10 ml of 0.1 ml of 0.1 M ammonia solution (pK_(b) = 5.0), the equivalence point occurs at pH

Answer»

`5.0`
`6.0`
`7.0`
`9.0`

SOLUTION :`pK_(a) = -LOG K_(sp)pK_(b) = -logK_(b)`
`pH = -(1)/(2)[log K_(a) + log K_(w) - log K_(b)]`
`= (1)/(2)[-5 + log(1 xx 10^(-14)) - (-5)]`
`= -(1)/(2)[-5-14+5] = -(1)/(2)(-14) =7`


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