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When 100 J of work is done on a fly wheel, its angular velocity is increased from 60 rpm to 180 rpm. What is the moment of inertia of the wheel? |
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Answer» SOLUTION :K.E=100 J,`n_(1)`=60 rpm =1 RPS,`n_(2)`=180 rpm =3rps Increase in kinetic energy `E=(1)/(2)I(omega_(2)^(2)-omega_(1)^(2))=(1)/(2)I(4pi^(2)n_(2)^(2)-4pi^(2)n_(1)^(2))` `100=(1)/(2)I(4pi^(2).9-4 pi^(2)1^(2))=2pi^(2)I(9-1)=16pi^(2).I` `therefore` momeny of inertia of the wheel I =`(100)/(16 mpi^(2))=0.633 kg m^(2)` |
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