1.

When 100 ml of 0.4 M CH_3 COOHis mixed with 100 ml of 0.2 M NaOH , the [H_3O]^(+)in the solution is approximately :[K_a (CH_3COOH)= 1.8 xx 10 ^(-5) ]

Answer»

`1.8 xx 10 ^(-4) `
` 1.8 xx 10 ^(-5)`
` 9 xx 10 ^(-6) `
` 9xx 10 ^(-5) `

SOLUTION :`[H^(+) ] =([CH_3COOH])/([CH_3COO^(-)]) `
` =1.8 xx 10 ^(-5)xx ( (100 xx 0.4- 100 xx 0.2))/( (100 xx 0.2 )) =1.8 xx 10 ^(_5)`


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