1.

When 100 mL of 1.0 M HCl was mixed 100 mL of 1.0 M NaOH in an insulated beaker at constant pressure, a temperature increase 5.7^(@)C was measured for the beaker and its contents (Expt. 1). Because the enthalpy of neutralization of a strong acid with a strong base is a constant (-57.0 kJmol^(-1)), this experiment could be used to measure the calorimeter constant. In a second experiment (Expt.2) 100 mL of 2.0 M acetic acid (K_(a)=2.0xx10^(-5)) was mixed with 100 mL of 1.0 M NaOH (under indentical conditions to Expt. 1) where a temperature rise of 5.6^(@)C was measured (Consider heat capacity of all solutions as 4.2 Jg^(-1)K^(-1) and density of al solutions as 1.0 gmL^(-1))Enthalpy of dissociation (in KJmol^(-1))of acetic acid obtained from the Expt.2 is

Answer»

`1.0`
`10.0`
`24.5`
`51.4`

Solution :Let the heat capacity of insulated beaker be C
Mass of aqueous content in expt.
`1=(100+100)xx1=200g`
implies Total heat capacity = `(C+200xx4.2)J//K`
Moles of acid, base neutralised in expt. `1=0.1xx1=0.1`
implies Heat released in expt. `1=0.1xx57=5.7 KJ`
`implies5.7xx1000=(C+200xx4.2)xxDeltaT`
`5.7xx1000=(C+200xx4.2)xx5.7`
`implies (C+200xx4.2)=1000`
In second experiment,
`n_(CH_(3)COOH)=0.2, n_(NAOH)=0.1`
Total mass of aqueous content = 200 g
implies Total heat capacity = (C+200`xx`4.2)=1000
implies Heat released = `1000xx5.6=5600 J`
Overall, only 0.1 mol of `CH_(3)COOH` undergo neutralization
`implies DeltaH_("neutralization")" of "CH_(3)COOH=(-5600)/(0.1)`
`=-56000 J//mol=-56 KJ//mol`
`impliesDeltaH_("IONIZATION")" of "CH_(3)COOH=57-56=1KJ//mol`


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