When 10g of a non-volatile solute is dissolved in 100 g of benzene, it raises boiling point by `1^(@)C` then molecular mass of the solute is (`K_(b)` for benzene `= 2.53 k-m^(-1)`)A. 223 gB. 233 gC. 243 gD. 253 g

When 10g of a non-volatile solute is dissolved in 100 g of benzene, it

1.	When 10g of a non-volatile solute is dissolved in 100 g of benzene, it raises boiling point by `1^(@)C` then molecular mass of the solute is (`K_(b)` for benzene `= 2.53 k-m^(-1)`)A. 223 gB. 233 gC. 243 gD. 253 g
Answer» Correct Answer - D `Delta T_(b)=(K_(b)xx w xx1000)/(m xx W)` `m=(K_(b)xx wxx 1000)/(Delta T_(b)xx W)=(2.53xx10xx1000)/(1xx100)=253 g`

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When 10g of a non-volatile solute is dissolved in 100 g of benzene, it raises boiling point by `1^(@)C` then molecular mass of the solute is (`K_(b)` for benzene `= 2.53 k-m^(-1)`)A. 223 gB. 233 gC. 243 gD. 253 g

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