When 159.5g of CuSo_4solution is reacted with KI, then the liberated iodine required 100 ml of 1 M Na_(2) S_(2)O_3for complete reaction, then what is the percentage purity of Cu in CuSO_4solution

When 159.5g of CuSo_4solution is reacted with KI, then the liberated i

1.	When 159.5g of CuSo_4solution is reacted with KI, then the liberated iodine required 100 ml of 1 M Na_(2) S_(2)O_3for complete reaction, then what is the percentage purity of Cu in CuSO_4solution
Answer» `10%` `20% ` ` 5%` `40%` Solution :No. of milli equivalents `Cu^(+2) = 100 ` `Cu^(+2) = 100 xx63.5 xx10^(-3) = 6.35 g` 159.5 of `CuSO_4` should CONTAIN = 63. 5 g of COPPER but only 6.35g Cu is PRESENT % purity = `(6.35 )/(63.5)xx100 = 10%`