1.

When 1F of electricity is passed acidulated water, O_(2) evolved

Answer»

11.2 `DM^(3)`
5.6 `dm^(3)`
22.4`dm^(3)`
1.0 `dm^(3)`

Solution :REACTION for electrolysis of water is:
`2H_(2)Oto4H^(+)+2O^(2-)`
Reaction for electrolysis of water is
`2H_(2)Oto4H^(+)+2O^(2-)`
`2O^(-)toO_(2)+4E^(-)`
`4e^(-)+4H^(+)to2H_(2)`
`becausen=4` so 4 faraday charge will leberate
1 mole=22.4 `dm^(3)` oxygen.
`therefore1` faraday charge will LIBERATE `(22.4)/(4)=5.6dm^(3)O_(2)`.


Discussion

No Comment Found

Related InterviewSolutions