1.

When 2.46 of hydrated salt `(MSO_(4)x H_(2)O)` is completely dehydrated, 1.20 g of anhydrous salt is obtained. It molecular weight of anhydrous salt is `120 g mol^(-1)`, the value of x isA. 2B. 4C. 5D. 7

Answer» Correct Answer - D
`underset(underset(2.46g)(2.46))(MSO_(4)xH_(2)O)rarrunderset(underset(120g)(1.2g))(MSO_(4))+xH_(2)O`
Weight of water `(H_(2)O)=(246 - 120) = 126 g`
No. of moles of water `(x) = (126 g)/(("18 g mol"^(-1))) = 7` mol.


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