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When (-)-2-bromooctane reacts with potassium hydroxide over an SN2 mechanism, what will be the product formed?(a) (-)-octan-1-ol(b) (+)-octan-1-ol(c) (-)-octan-2-ol(d) (+)-octan-2-olI had been asked this question during an interview.This interesting question is from Haloalkanes & Haloarenes in division Haloalkanes and Haloarenes of Chemistry – Class 12 |
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Answer» The correct choice is (d) (+)-octan-2-ol |
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