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When (-)-2-bromooctane reacts with potassium hydroxide over an SN2 mechanism, what will be the product formed?(a) (-)-octan-1-ol(b) (+)-octan-1-ol(c) (-)-octan-2-ol(d) (+)-octan-2-olI had been asked this question during an interview.This interesting question is from Haloalkanes & Haloarenes in division Haloalkanes and Haloarenes of Chemistry – Class 12

Answer»

The correct choice is (d) (+)-octan-2-ol

Explanation: The OH NUCLEOPHILE attaches itself OPPOSITE to where the halide was PRESENT but one the same carbon. This results in an inversion of configuration and hence changes in the direction in which the plane of polarised LIGHT rotates.



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