When 2 mol of \( CoCl _{3}\left( NH _{3}\right)_{5} \) is treated with

1.	When 2 mol of \( CoCl _{3}\left( NH _{3}\right)_{5} \) is treated with excess amount of \( AgNO _{3}, 4 \) mol of \( AgCl \) is obtained. The conductivity of solution will correspond to A. \( 1: 3 \) electrolyteB. 1: 1 electrolyte C. \( 1: 2 \) electrolyte D. 3:1 electrolyte
Answer» Correct option is (c) electrolyte \(\because\) 2 mol of CoCl₃(NH₃)₅, on treated with excess amount of AgNO₃ gives 4 mol Agcl, it means two chlorine atoms are in outer sphere. \(\underset{2\,mol}{[Co(NH_3)_5Cl]Cl_2}\) + \(\underset{excess}{AgNO_3 }\) \(\longrightarrow\) \(\underset{2\,mol}{[Co(NH_3)_5]Cl}^{+2}+\underset{4mol}{Agcl}\) Conductivity of solution, due to presence of Ag⁺, \(NO_3^-\) and [Co(NH₃)₅Cl]⁺² ions only. \(\therefore\) The conductivity of solution will correspond 1 : 2 electrolyte.

When 2 mol of \( CoCl _{3}\left( NH _{3}\right)_{5} \) is treated with excess amount of \( AgNO _{3}, 4 \) mol of \( AgCl \) is obtained. The conductivity of solution will correspond to A. \( 1: 3 \) electrolyteB. 1: 1 electrolyte C. \( 1: 2 \) electrolyte D. 3:1 electrolyte

Answer»

Correct option is (c) electrolyte

\(\because\) 2 mol of CoCl₃(NH₃)₅, on treated with excess amount of AgNO₃ gives 4 mol Agcl, it means two chlorine atoms are in outer sphere.

\(\underset{2\,mol}{[Co(NH_3)_5Cl]Cl_2}\) + \(\underset{excess}{AgNO_3 }\) \(\longrightarrow\) \(\underset{2\,mol}{[Co(NH_3)_5]Cl}^{+2}+\underset{4mol}{Agcl}\)

Conductivity of solution, due to presence of Ag⁺, \(NO_3^-\) and [Co(NH₃)₅Cl]⁺² ions only.

\(\therefore\) The conductivity of solution will correspond 1 : 2 electrolyte.

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