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When 3-methylbutan-2-ol is treated with HBr, the following reaction takes place : CH_3-underset(CH_3)underset(|)CH-underset(OH)underset(|)CH-CH_3 overset(HBr)to CH_3 underset(CH_3)underset(|)overset(Br)overset(|)C-CH_2 - CH_3Give a mechanism for this reaction (Hint : The secondary carbocation formed in step-II rearranges to a more stable tertiary carbocation by a hydribe ion shift from 3rd carbon atom). |
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Answer» Solution :Step-1: Protonation `underset("3-Methylbutan-2-ol")(CH_3-underset(CH_3)underset(|)CH-underset(OH)underset(|)CH-CH_3) OVERSET(H^+)to CH_3-underset(CH_3)underset(|)CH-underset(+)underset(OH_2)underset(|)CH-CH_3` Step-2:FORMATION of `2^@` CARBOCATION by elimination ofa water molecule
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