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When 3 - methylbutan -2- ol is treated with HBr, the following reaction takes place : CH_(3)-underset(CH_(3))underset("|")"CH"-underset(OH)underset("|")"CH"-CH_(3)overset(HBr)rarrCH_(3)-overset("Br")overset("|")underset(CH_(3))underset("|")"C "-CH_(2)-CH_(3) Give a mechanism for this reaction. |
Answer» Solution :Protonation of the given ALCOHOL followed by loss of water gives a `2^(@)` CARBOCATION (I) which rearranges by 1,2- hydride SHIFT to form the more stable `3^(@)` carbocation (II). Nucleophilic attack by `Br^(-)` ION on this carbocation (II) gives the final product.
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