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When 32.25 g of ethyl chloride is subjected to dehydrohalogenation reaction, the yield of alkene formed is 50%. The mass of the product formed is (atomic mass of Cl = 35.5)A. 14 gB. 28 gC. `66.5 g`D. 7 g |
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Answer» Correct Answer - D `underset(64.5g)(CH_(3)CH_(2)Cl)overset(KOH(alc.)Delta)underset(-KCl, -H_(2)O)rarrunderset(28 g)(CH_(2)=CH_(2))` yield of `CH_(2)=CH_(2)=(28)/(64.5)xx(32.25xx56)/(100)=7 g` |
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