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InterviewSolution
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When `32.25` gm ethyl chloride dehydrohalogenated. It gives `50%` alkene what is the mass of product. (Atomic mass of chlorine `= 35.5`)A. 14 gmB. 28 gmC. `64.5` gmD. 7 gm |
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Answer» `CH_(2)H_(5)Cloverset(-HCl)rarrC_(2)H_(4)` `{:(64.5" "28),(32.25" "14):}` `64.5gm C_(2)H_(5)Cl` gives `28 gm` of `C_(2)H_(4)` `32.25 gm C_(2)H_(5)Cl` gives `= (28 xx 32.25)/(64.5) = 14` `= 14 gm` of `C_(2)H_(4)` Obtained producted is `50%` so mass of obtained alkene `=(14)/(2) = 7 gm`. |
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