When 4 gm of Mg burnt with O_(2) form oxide and on dilution of metal oxide form metal hydroxide which statement is/are correct for above series of reaction?

When 4 gm of Mg burnt with O_(2) form oxide and on dilution of metal o

1.	When 4 gm of Mg burnt with O_(2) form oxide and on dilution of metal oxide form metal hydroxide which statement is/are correct for above series of reaction?
Answer» Gram equivalent of metal, metal oxide an metal hydroxide are equal Weight of metal oxide is 6.66 gm Weight of metal hydroxide is 9.66 gm Normality of SOLUTION in 1 LITRE volume is `(14)/(42)` Solution :`2Mg+O_(2)rarr2MgO` `MgO+H_(2)OrarrMg(OH)_(2)` Eq. of MG = Eq. of Mgo = Eq. of `Mg(OH)_(2)` `(4)/(12)=(W)/(20)impliesW=6.66gm` `therefore` Eq of MgO = 6.66 Eq. of Mg = Eq. of `Mg(OH)_(2)` `(4)/(12)=(w)/(29)impliesW=(29)/(3)=9.66gm`