When 6.3 g of NaHCO_(3) (sodium bicarbonate) is added to a solution of CH_(3)COOH (acetic acid) weighing 15 g, it is observed that 3.3 g CO_(2) is released to the atmosphere. The residue is found to weigh 18.0 g. Show that the data is in agreement with the law of conservation of mass.

When 6.3 g of NaHCO_(3) (sodium bicarbonate) is added to a solution of

1.	When 6.3 g of NaHCO_(3) (sodium bicarbonate) is added to a solution of CH_(3)COOH (acetic acid) weighing 15 g, it is observed that 3.3 g CO_(2) is released to the atmosphere. The residue is found to weigh 18.0 g. Show that the data is in agreement with the law of conservation of mass.
Answer» Solution :The chemical EQUATION for the reaction is : `NaHCO_(3)+CH_(2)COOHrarrCH_(3)COONa+H_(2)O+CO_(2)` Sod. Bicarbonate Acetic ACID `underset(("Residue"))(underbrace("Sod. acetate"))` Mass of reactants = Mass of `NaHCO_(3) + "Mass of "CH_(3)COOH = 6.3 + 15 = 21.3 g` Mass of product = Mass of residue + Mass of `CO_(2)=18 + 3.3 = 21.3 g` Since these is no change in mass during the chemical reaction the DATA illustrates the Law of conservation of Mass.