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When 6 gm urea dissolve in `18 gm H_(2)O`. The mole fraction of urea isA. `(10)/(10.1)`B. `(10.1)/(10)`C. `(10.1)/(0.1)`D. `(0.1)/(10.1)` |
Answer» Correct Answer - D Mole fraction `X=(n)/(n + N)=((6)/(60))/((6)/(60)+(180)/(18))=(0.1)/(10.1)`. |
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