Saved Bookmarks
| 1. |
When `._(92)U^(238)` decauys it emits an a-particle. The new nuclide in turn emits a beta-particele to give another nuclide X. The mass number and atomic number of X are. Respectively .A. ` 234 ` and ` 91`B. ` 234 `and ` 96`C. ` 231` and ` 88`D. ` 234` and ` 88` |
|
Answer» Correct Answer - A `. _(92) U^(238) rarr _zX^A +_2 H_(e)^(4)+_(-1)e^0` Equating mass number on both sides ` 238 = A+4 0` ` :. A= 238 - 4 = 234` Equating atomic numer on both sides ` 92 = Z + 2 -1` ` :. Z= 92 -1 =91`. |
|