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When a `2 mu C` charge is carried from point A to point B, the amount of work done by the electric field is `50 mu J`. What is the potential difference and which point is at a higher potential ? |
Answer» `V_(B) - V_(A) = (wo rk)/(charg e) = (50 muJ)/(2 muC) = 25 vol t`. Clearly, `V_(B) gt V_(A)`. |
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