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When a 4V battery is connected across an unknown resistor there is a current of 100 mA in the circuit. The value of the resistance of the resister is: (i) 4 Ω (ii) 40 Ω (iii) 400 Ω (iv) 0.4 Ω |
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Answer» (ii) = 40 Ω. V=IR, V = 4V, I = 100 mA = 0.1 A Hence R = V/I = 4/0.1 Ω = 40 Ω. |
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