When a bady undergoes an oblique projection, maximum rangeof it is :

1.	When a bady undergoes an oblique projection, maximum rangeof it is :
Answer» `(U^(2))/(g)` `(u)/(g)` `(u^(2))/(g^(2))` `(u^(2))/(2g)` SOLUTION :`R= (u^(2))/(g) SIN2 theta` Here `theta = 45^(@)` `R = (u^(2))/(g) sin 90^(@) = (u^(2))/(g)`

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