1.

When a ball is thrown up vertically with velocity v_(0) it reaches a maximumheight ofh. when the ball reaches to triple t he maximum height. The velocity with which the ball was thrown is:

Answer»

`3v_(0)`
`9v_(0)`
`sqrt(3)v_(0)`
`2v_(0)`

Solution :`V^(2) - U^(2) = 2AS`
Here ` u = v_(0), s = h, v = 0 , a = - g`
`0^(2) - v_(0)^(2) - 2 (-g)h`
`:. v_(0)^(2) = 2gh""i.e., v_(0)^(2) prop h`
i,e.,`v_(0)^(2) prop 3h`
`(v'_(0)^(2))/(v'_(0)^(2))= (3h)/(h) = 3 `
`:. v'_(0)^(2)= 3 v_(0)^(2) `
`:. v'_(0) = sqrt(3) v_(0)`


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